3.8.62 \(\int \frac {\sqrt {x}}{(a+c x^4)^3} \, dx\) [762]

Optimal. Leaf size=329 \[ \frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}} \]

[Out]

1/8*x^(3/2)/a/(c*x^4+a)^2+13/64*x^(3/2)/a^2/(c*x^4+a)+65/256*arctan(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(21/8)/c^
(3/8)-65/256*arctanh(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(21/8)/c^(3/8)-65/512*arctan(-1+c^(1/8)*2^(1/2)*x^(1/2)/
(-a)^(1/8))/(-a)^(21/8)/c^(3/8)*2^(1/2)-65/512*arctan(1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)^(1/8))/(-a)^(21/8)/c^(3/8
)*2^(1/2)-65/1024*ln((-a)^(1/4)+c^(1/4)*x-(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(21/8)/c^(3/8)*2^(1/2)+65/1
024*ln((-a)^(1/4)+c^(1/4)*x+(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(21/8)/c^(3/8)*2^(1/2)

________________________________________________________________________________________

Rubi [A]
time = 0.22, antiderivative size = 329, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {296, 335, 306, 303, 1176, 631, 210, 1179, 642, 304, 211, 214} \begin {gather*} \frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \text {ArcTan}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}+\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[x]/(a + c*x^4)^3,x]

[Out]

x^(3/2)/(8*a*(a + c*x^4)^2) + (13*x^(3/2))/(64*a^2*(a + c*x^4)) + (65*ArcTan[1 - (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a
)^(1/8)])/(256*Sqrt[2]*(-a)^(21/8)*c^(3/8)) - (65*ArcTan[1 + (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*Sqrt[
2]*(-a)^(21/8)*c^(3/8)) + (65*ArcTan[(c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(21/8)*c^(3/8)) - (65*ArcTanh[(c
^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(21/8)*c^(3/8)) - (65*Log[(-a)^(1/4) - Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[
x] + c^(1/4)*x])/(512*Sqrt[2]*(-a)^(21/8)*c^(3/8)) + (65*Log[(-a)^(1/4) + Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sqrt[x] +
 c^(1/4)*x])/(512*Sqrt[2]*(-a)^(21/8)*c^(3/8))

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 296

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-(c*x)^(m + 1))*((a + b*x^n)^(p + 1)/
(a*c*n*(p + 1))), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; Free
Q[{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 303

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
 b]]))

Rule 304

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}
, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !
GtQ[a/b, 0]

Rule 306

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b
, 2]]}, Dist[r/(2*a), Int[x^m/(r + s*x^(n/2)), x], x] + Dist[r/(2*a), Int[x^m/(r - s*x^(n/2)), x], x]] /; Free
Q[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LtQ[m, n/2] &&  !GtQ[a/b, 0]

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
 && FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 631

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[a*(c/b^2)]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
 FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 642

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[d*(Log[RemoveContent[a + b*x +
c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1176

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[2*(d/e), 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
 x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1179

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[-2*(d/e), 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {\sqrt {x}}{\left (a+c x^4\right )^3} \, dx &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 \int \frac {\sqrt {x}}{\left (a+c x^4\right )^2} \, dx}{16 a}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \int \frac {\sqrt {x}}{a+c x^4} \, dx}{128 a^2}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \text {Subst}\left (\int \frac {x^2}{a+c x^8} \, dx,x,\sqrt {x}\right )}{64 a^2}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}-\frac {65 \text {Subst}\left (\int \frac {x^2}{\sqrt {-a}-\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 (-a)^{5/2}}-\frac {65 \text {Subst}\left (\int \frac {x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 (-a)^{5/2}}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}-\frac {65 \text {Subst}\left (\int \frac {1}{\sqrt [4]{-a}-\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 (-a)^{5/2} \sqrt [4]{c}}+\frac {65 \text {Subst}\left (\int \frac {1}{\sqrt [4]{-a}+\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 (-a)^{5/2} \sqrt [4]{c}}+\frac {65 \text {Subst}\left (\int \frac {\sqrt [4]{-a}-\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 (-a)^{5/2} \sqrt [4]{c}}-\frac {65 \text {Subst}\left (\int \frac {\sqrt [4]{-a}+\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 (-a)^{5/2} \sqrt [4]{c}}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \text {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 (-a)^{5/2} \sqrt {c}}-\frac {65 \text {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 (-a)^{5/2} \sqrt {c}}-\frac {65 \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}+2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}-2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}\\ &=\frac {x^{3/2}}{8 a \left (a+c x^4\right )^2}+\frac {13 x^{3/2}}{64 a^2 \left (a+c x^4\right )}+\frac {65 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}-\frac {65 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{21/8} c^{3/8}}-\frac {65 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}+\frac {65 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{21/8} c^{3/8}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 1.00, size = 287, normalized size = 0.87 \begin {gather*} \frac {\frac {8 a^{5/8} x^{3/2} \left (21 a+13 c x^4\right )}{\left (a+c x^4\right )^2}+\frac {65 \sqrt {2-\sqrt {2}} \tan ^{-1}\left (\frac {\sqrt {1-\frac {1}{\sqrt {2}}} \left (\sqrt [4]{a}-\sqrt [4]{c} x\right )}{\sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}\right )}{c^{3/8}}-\frac {65 \sqrt {2+\sqrt {2}} \tan ^{-1}\left (\frac {\sqrt {1+\frac {1}{\sqrt {2}}} \left (\sqrt [4]{a}-\sqrt [4]{c} x\right )}{\sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}\right )}{c^{3/8}}+\frac {65 \sqrt {2-\sqrt {2}} \tanh ^{-1}\left (\frac {\sqrt {2+\sqrt {2}} \sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}{\sqrt [4]{a}+\sqrt [4]{c} x}\right )}{c^{3/8}}-\frac {65 \sqrt {2+\sqrt {2}} \tanh ^{-1}\left (\frac {\sqrt [8]{a} \sqrt [8]{c} \sqrt {-\left (\left (-2+\sqrt {2}\right ) x\right )}}{\sqrt [4]{a}+\sqrt [4]{c} x}\right )}{c^{3/8}}}{512 a^{21/8}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[x]/(a + c*x^4)^3,x]

[Out]

((8*a^(5/8)*x^(3/2)*(21*a + 13*c*x^4))/(a + c*x^4)^2 + (65*Sqrt[2 - Sqrt[2]]*ArcTan[(Sqrt[1 - 1/Sqrt[2]]*(a^(1
/4) - c^(1/4)*x))/(a^(1/8)*c^(1/8)*Sqrt[x])])/c^(3/8) - (65*Sqrt[2 + Sqrt[2]]*ArcTan[(Sqrt[1 + 1/Sqrt[2]]*(a^(
1/4) - c^(1/4)*x))/(a^(1/8)*c^(1/8)*Sqrt[x])])/c^(3/8) + (65*Sqrt[2 - Sqrt[2]]*ArcTanh[(Sqrt[2 + Sqrt[2]]*a^(1
/8)*c^(1/8)*Sqrt[x])/(a^(1/4) + c^(1/4)*x)])/c^(3/8) - (65*Sqrt[2 + Sqrt[2]]*ArcTanh[(a^(1/8)*c^(1/8)*Sqrt[-((
-2 + Sqrt[2])*x)])/(a^(1/4) + c^(1/4)*x)])/c^(3/8))/(512*a^(21/8))

________________________________________________________________________________________

Maple [C] Result contains higher order function than in optimal. Order 9 vs. order 3.
time = 0.15, size = 62, normalized size = 0.19

method result size
derivativedivides \(\frac {\frac {21 x^{\frac {3}{2}}}{64 a}+\frac {13 c \,x^{\frac {11}{2}}}{64 a^{2}}}{\left (x^{4} c +a \right )^{2}}+\frac {65 \left (\munderset {\textit {\_R} =\RootOf \left (c \,\textit {\_Z}^{8}+a \right )}{\sum }\frac {\ln \left (\sqrt {x}-\textit {\_R} \right )}{\textit {\_R}^{5}}\right )}{512 a^{2} c}\) \(62\)
default \(\frac {\frac {21 x^{\frac {3}{2}}}{64 a}+\frac {13 c \,x^{\frac {11}{2}}}{64 a^{2}}}{\left (x^{4} c +a \right )^{2}}+\frac {65 \left (\munderset {\textit {\_R} =\RootOf \left (c \,\textit {\_Z}^{8}+a \right )}{\sum }\frac {\ln \left (\sqrt {x}-\textit {\_R} \right )}{\textit {\_R}^{5}}\right )}{512 a^{2} c}\) \(62\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/2)/(c*x^4+a)^3,x,method=_RETURNVERBOSE)

[Out]

2*(21/128*x^(3/2)/a+13/128/a^2*c*x^(11/2))/(c*x^4+a)^2+65/512/a^2/c*sum(1/_R^5*ln(x^(1/2)-_R),_R=RootOf(_Z^8*c
+a))

________________________________________________________________________________________

Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)/(c*x^4+a)^3,x, algorithm="maxima")

[Out]

1/64*(13*c*x^(11/2) + 21*a*x^(3/2))/(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4) + 65*integrate(1/128*sqrt(x)/(a^2*c*x^4
+ a^3), x)

________________________________________________________________________________________

Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 665 vs. \(2 (224) = 448\).
time = 0.40, size = 665, normalized size = 2.02 \begin {gather*} -\frac {260 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {a^{16} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{4}} + \sqrt {2} a^{8} c \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + x} a^{13} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}} - \sqrt {2} a^{13} c^{2} \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}} + 1\right ) + 260 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {2} \sqrt {a^{16} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{4}} - \sqrt {2} a^{8} c \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + x} a^{13} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}} - \sqrt {2} a^{13} c^{2} \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}} - 1\right ) - 65 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \log \left (a^{16} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{4}} + \sqrt {2} a^{8} c \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + x\right ) + 65 \, \sqrt {2} {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \log \left (a^{16} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{4}} - \sqrt {2} a^{8} c \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + x\right ) - 520 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \arctan \left (\sqrt {a^{16} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{4}} + x} a^{13} c^{2} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}} - a^{13} c^{2} \sqrt {x} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {5}{8}}\right ) + 130 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \log \left (a^{8} c \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) - 130 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )} \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {1}{8}} \log \left (-a^{8} c \left (-\frac {1}{a^{21} c^{3}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) - 16 \, {\left (13 \, c x^{5} + 21 \, a x\right )} \sqrt {x}}{1024 \, {\left (a^{2} c^{2} x^{8} + 2 \, a^{3} c x^{4} + a^{4}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)/(c*x^4+a)^3,x, algorithm="fricas")

[Out]

-1/1024*(260*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1/8)*arctan(sqrt(2)*sqrt(a^16*c^2*(-1/
(a^21*c^3))^(3/4) + sqrt(2)*a^8*c*sqrt(x)*(-1/(a^21*c^3))^(3/8) + x)*a^13*c^2*(-1/(a^21*c^3))^(5/8) - sqrt(2)*
a^13*c^2*sqrt(x)*(-1/(a^21*c^3))^(5/8) + 1) + 260*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1
/8)*arctan(sqrt(2)*sqrt(a^16*c^2*(-1/(a^21*c^3))^(3/4) - sqrt(2)*a^8*c*sqrt(x)*(-1/(a^21*c^3))^(3/8) + x)*a^13
*c^2*(-1/(a^21*c^3))^(5/8) - sqrt(2)*a^13*c^2*sqrt(x)*(-1/(a^21*c^3))^(5/8) - 1) - 65*sqrt(2)*(a^2*c^2*x^8 + 2
*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1/8)*log(a^16*c^2*(-1/(a^21*c^3))^(3/4) + sqrt(2)*a^8*c*sqrt(x)*(-1/(a^21*c
^3))^(3/8) + x) + 65*sqrt(2)*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1/8)*log(a^16*c^2*(-1/(a^21*c^
3))^(3/4) - sqrt(2)*a^8*c*sqrt(x)*(-1/(a^21*c^3))^(3/8) + x) - 520*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21
*c^3))^(1/8)*arctan(sqrt(a^16*c^2*(-1/(a^21*c^3))^(3/4) + x)*a^13*c^2*(-1/(a^21*c^3))^(5/8) - a^13*c^2*sqrt(x)
*(-1/(a^21*c^3))^(5/8)) + 130*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1/8)*log(a^8*c*(-1/(a^21*c^3)
)^(3/8) + sqrt(x)) - 130*(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)*(-1/(a^21*c^3))^(1/8)*log(-a^8*c*(-1/(a^21*c^3))^(3
/8) + sqrt(x)) - 16*(13*c*x^5 + 21*a*x)*sqrt(x))/(a^2*c^2*x^8 + 2*a^3*c*x^4 + a^4)

________________________________________________________________________________________

Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(1/2)/(c*x**4+a)**3,x)

[Out]

Timed out

________________________________________________________________________________________

Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 472 vs. \(2 (224) = 448\).
time = 0.70, size = 472, normalized size = 1.43 \begin {gather*} -\frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} - \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (-\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} + \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (-\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} - \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (-\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {2 \, \sqrt {2} + 4}} - \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {65 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (-\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{3} \sqrt {-2 \, \sqrt {2} + 4}} + \frac {13 \, c x^{\frac {11}{2}} + 21 \, a x^{\frac {3}{2}}}{64 \, {\left (c x^{4} + a\right )}^{2} a^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)/(c*x^4+a)^3,x, algorithm="giac")

[Out]

-65/256*(a/c)^(3/8)*arctan((sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + 2*sqrt(x))/(sqrt(sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*
sqrt(2*sqrt(2) + 4)) - 65/256*(a/c)^(3/8)*arctan(-(sqrt(-sqrt(2) + 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(sqrt(2) +
 2)*(a/c)^(1/8)))/(a^3*sqrt(2*sqrt(2) + 4)) + 65/256*(a/c)^(3/8)*arctan((sqrt(sqrt(2) + 2)*(a/c)^(1/8) + 2*sqr
t(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*sqrt(-2*sqrt(2) + 4)) + 65/256*(a/c)^(3/8)*arctan(-(sqrt(sqrt(2)
+ 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^3*sqrt(-2*sqrt(2) + 4)) + 65/512*(a/c)^(3/8
)*log(sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(2*sqrt(2) + 4)) - 65/512*(a/c)^(3/8)*
log(-sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(2*sqrt(2) + 4)) - 65/512*(a/c)^(3/8)*l
og(sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(-2*sqrt(2) + 4)) + 65/512*(a/c)^(3/8)*l
og(-sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^3*sqrt(-2*sqrt(2) + 4)) + 1/64*(13*c*x^(11/2)
 + 21*a*x^(3/2))/((c*x^4 + a)^2*a^2)

________________________________________________________________________________________

Mupad [B]
time = 1.08, size = 157, normalized size = 0.48 \begin {gather*} \frac {\frac {21\,x^{3/2}}{64\,a}+\frac {13\,c\,x^{11/2}}{64\,a^2}}{a^2+2\,a\,c\,x^4+c^2\,x^8}+\frac {65\,\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}}{{\left (-a\right )}^{1/8}}\right )}{256\,{\left (-a\right )}^{21/8}\,c^{3/8}}+\frac {\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}\,1{}\mathrm {i}}{{\left (-a\right )}^{1/8}}\right )\,65{}\mathrm {i}}{256\,{\left (-a\right )}^{21/8}\,c^{3/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (-\frac {65}{512}+\frac {65}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{21/8}\,c^{3/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (-\frac {65}{512}-\frac {65}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{21/8}\,c^{3/8}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/2)/(a + c*x^4)^3,x)

[Out]

((21*x^(3/2))/(64*a) + (13*c*x^(11/2))/(64*a^2))/(a^2 + c^2*x^8 + 2*a*c*x^4) + (65*atan((c^(1/8)*x^(1/2))/(-a)
^(1/8)))/(256*(-a)^(21/8)*c^(3/8)) + (atan((c^(1/8)*x^(1/2)*1i)/(-a)^(1/8))*65i)/(256*(-a)^(21/8)*c^(3/8)) - (
2^(1/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 - 1i/2))/(-a)^(1/8))*(65/512 - 65i/512))/((-a)^(21/8)*c^(3/8)) - (2
^(1/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 + 1i/2))/(-a)^(1/8))*(65/512 + 65i/512))/((-a)^(21/8)*c^(3/8))

________________________________________________________________________________________